Default
Question
Find the derivative of x2−32x+1
Solution
The correct answer is 2(x2+x+3)(2x+1)2
Explanation
As per Quotient Rule,
dydx = vdudx−udvdxv2
∴ \dfrac{dy}{dx} = \dfrac{(2x + 1) D(x^2 - 3) - (x^2 - 3) D(2x + 1)}{(2x + 1)^2}
= \dfrac{(2x + 1)(2x) - (x^2 - 3) (2)}{(2x + 1)^2}
= \dfrac{4x^2 + 2x - 2x^2 + 6 )}{(2x + 1)^2}
= \dfrac{2 (x^2 + x + 3)}{(2x + 1)^2}
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